Using the digits 0-9 form five two-digit numbers, which form an arithmetic sequence.

Find the sum of the numbers in all the possible arithmetic sequences that can occur.

total  = 0  

for a in range (72):  

    gap = 100-a  

    maxt2t = (gap//4) + 1  

    for t2t in range(7,maxt2t):  

        b, c, d, e = a + t2t, a + 2*t2t, a + 3*t2t, a + 4*t2t        

        ans = ''.join(sorted(str(a) + str(b) + str(c) + str(d) + str(e)))  

        if ans == '0123456789' or ans == '123456789':  

            print(a,b,c,d,e)  

            total += a + b + c + d + e  

print ("Total = ", total)  

It gives an output like this:

1 23 45 67 89  

5 16 27 38 49  

9 18 27 36 45  

9 27 45 63 81  

10 32 54 76 98  

18 36 54 72 90  

50 61 72 83 94  

54 63 72 81 90  

Total =  1980